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The scenario:
I recently got my new laptop which runs Vista Ultimate. The laptop HD setup is: (RAID 0) - 160GB (80GB x 2) Serial ATA. I have a program for school that will only run on 2000/XP and also under IE6 only. What I want to do is dual boot Vista and XP for the time being, and then after the summer semester, I hopefully won’t need XP anymore, so I can get rid of it on the laptop. I want to set the laptop up with C: (Vista) D: (XP) and E: (Misc).

The Question:
There are plenty of tutorials online on how to dual boot Vista and XP, that’s not a problem. My question/concern is, how do I do this on a RAID 0 system? I know that Windows shows there to be 160GB, but is that full 160GB usable? Can I have 70GB for “C:” 70 GB for “D:” and 20GB for “E:”? This doesn’t make sense to me, but that is how it looks based upon the total drive size. My understanding of a RAID setup, is that HDD(B) is supposed to be an exact copy of HDD(A). I still don’t understand how Windows recognizes this as 160GB, I would think that only 80 of it should be usable. If someone could please explain this to me it would be much appreciated.
The scenario:
I recently got my new laptop (see system in profile), which runs Vista Ultimate. The laptop HD setup is: (RAID 0) - 160GB (80GB x 2) Serial ATA. I have a program for school that will only run on 2000/XP and also under IE6 only. What I want to do is dual boot Vista and XP for the time being, and then after the summer semester, I hopefully won’t need XP anymore, so I can get rid of it on the laptop. I want to set the laptop up with C: (Vista) D: (XP) and E: (Misc).

The Question:
There are plenty of tutorials online on how to dual boot Vista and XP, that’s not a problem. My question/concern is, how do I do this on a RAID 0 system? I know that Windows shows there to be 160GB, but is that full 160GB usable? Can I have 70GB for “C:” 70 GB for “D:” and 20GB for “E:”? This doesn’t make sense to me, but that is how it looks based upon the total drive size. My understanding of a RAID setup, is that HDD(B) is supposed to be an exact copy of HDD(A). I still don’t understand how Windows recognizes this as 160GB, I would think that only 80 of it should be usable. If someone could please explain this to me it would be much appreciated.