C Programming Problem

[Manakore]

I have to write a program that allows the user to enter in characters in the keyboard until # is executed. At this point the program will post results.

The number of alphabetical letters
The number of spaces
The number of digits
The sum of digits

The problem is, I have no idea how to get the program to count the sum of digits properly. Since I am entering characters, the number is not registered as an integer so when it adds the sum, the result is incorrect. Any help will be much appreciated. Thanks!

#include <stdio.h>
#include <ctype.h>
#include <conio.h>
#include <limits.h>

int main(void)
{
char character;
int num_alpha = 0;
int num_spaces = 0;
int num_digits = 0;
int sum_digits = 0;
int num_min = INT_MIN;
int num_max = INT_MAX;
int a = 0;

while((character = getchar()) != '#')
{
putchar(character);
if(isalpha(character))
num_alpha+=1;
else if(character == ' ')
num_spaces+=1;
else if(character == '\t' || character == '\n' || character == '#')
num_alpha+=0;
else
{
sum_digits +=character;
num_digits++;
}
}


printf("\n");
printf("The number of alphabetical characters is %d.\n",num_alpha);
printf("The number of spaces is %d.\n",num_spaces);
printf("The number of digits is %d.\n",num_digits);
printf("The sum of the digits is %d.\n",sum_digits);


return 0;
}

 

[Troncoso]

atoi(&someChar); //Converts a char to an int

Be sure to put an if statement or something with it so it only tries to convert numbers.

 

[Manakore]

atoi(&someChar); //Converts a char to an int

Be sure to put an if statement or something with it so it only tries to convert numbers.

This was exactly what I was looking for thanks!

 

[Manakore]

That actually deals with strings though, which unfortunately we haven't learned yet and thus I cannot use it. Is there any other way to go about this problem?

 

[Troncoso]

That actually deals with strings though, which unfortunately we haven't learned yet and thus I cannot use it. Is there any other way to go about this problem?

It should work for a char. A string in C is nothing more than an array of char's either way.

I may be mistaken, though. It's been a while since I've used C.

Supposedly, this will also work:

int x = myChar - '0';

 

[Cromewell]

Supposedly, this will also work:

int x = myChar - '0';

Yes that will also work. Assuming your entered number is a single digit (in which in this case it will be). However, you'll have to be careful, chars can be treated as integers very easily in C and something like 'a' - '0' will execute.

 

[Manakore]

It should work for a char. A string in C is nothing more than an array of char's either way.

I may be mistaken, though. It's been a while since I've used C.

Supposedly, this will also work:

int x = myChar - '0';

This worked thanks a lot sir!