Cooler-less Celeron?/ CPU Frying.... WOOT!!!

I remember my old P133 system, the CPU just had a small AL heatsink (like Cromewell, above) and no heatsink on the north bridge. I would run it for a few mins, feel the mobo, and almost burn myself on the chipset lol. That was back when there was a seperate slot for the 128KB of cache for the CPU.
 
Edit: Energy is neither lost nor created, only transfered... Electricity is a form of energy.... the reason a computer creates heat is the friction created when electricity flows through something. In process of creating that heat, you lose that amount of electricity respectively... (forgot the term, i think watts or something...). More friction equals less electricity and more heat. Less friction equals more electricity and less heat. The reason why a computer creates heat is because it's flawed with friction and ineffiency. (Something that is a good conductor has very little electrical resistance.... or friction....) The perfect computer would, in essence, would require almost no electricity and would emit no heat. The only place where there exists no friction is in a absolute vacuum. (The is also the reason why we get burned if we're shocked, as human bodies are poor conductors.....)

I think I got that right....
 
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well.. a part goes back to the PSU,. and a part is dissipated
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Well, if part goes back to the PSU then it isn't really used. The electrons that return (since it is a circuit) having a lower voltage potential. Kind of like have a ball fall to the ground - it had potential energy (which was turned to kinetic energy), and relative to, say the earth's core, it still has potential energy, but for all intents and purposes it can't do anything more.
but seriously.. if all the energy would be converted to hear, the pc wouldnt do anything at all.. a big deal of the energy is used to throw all the 'switches' inside the processor, the IC's on the motherboard etc.
ofcourse.. with every time you swich a Ic or something like that, you loose energy in Heat,.. but never everything
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All energy eventually ends up as heat thanks to the second law of thermodynamics, and as such heat is considered a "low grade energy."

Anyway, this is a bit off topic and I'm sorry to have instigated this little arguement. As for the Celeron - I wouldn't think it would really last, most older CPUs don't even have heat spreaders, just a bare core (and thus very poor convective heat transfer).
 
Let me try this again.....

Energy is neither lost nor created, only transfered... Electricity is, thus, a form of energy.... The reason a computer creates, or for most electronics that matter, heat is the resistance created when electricity flows through something. You lose electricity from resistance, respectively through heat... If something is a good conductor, electricity easliy flows through it and very little electricity is loss through heat.... The perfect conductor is something with little electrical resistance. The reason why a computer creates heat is it's ineffiency from electrical resistance.... A better, cooler computer, in essence, is a better conductor.....

I think I got that right....
 
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Many older processors (early 486s and earlier) had no heatsink at all. Many slightly more modern computers (i.e. early pentiums) had either a passive heatsink only, or a small active cooler. In some cases this could be removed for long periods of time without damaging the computer.
 
bumblebee_tuna said:
Let me try this again.....

Energy is neither lost nor created, only transfered... Electricity is, thus, a form of energy.... The reason a computer creates, or for most electronics that matter, heat is the resistance created when electricity flows through something. You lose electricity from resistance, respectively through heat... If something is a good conductor, electricity easliy flows through it and very little electricity is loss through heat.... The perfect conductor is something with little electrical resistance. The reason why a computer creates heat is it's ineffiency from electrical resistance.... A better, cooler computer, in essence, is a better conductor.....

I think I got that right....
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thats right.. and if a CPU would dissipate all energy to heat, it theoretically would have an infinite resistance, and couldnt do anything
 
thats right.. and if a CPU would dissipate all energy to heat, it theoretically would have an infinite resistance, and couldnt do anything
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Not true. An infinite resistance, i.e. and open circuit, uses no power and thus generates no heat.

Thought experiment: I have a 12 volt power supply (for simplicity we'll say it's DC) and a resistive load of 10 ohms. How much power does it use?
 
Yeti said:
Not true. An infinite resistance, i.e. and open circuit, uses no power and thus generates no heat.

Thought experiment: I have a 12 volt power supply (for simplicity we'll say it's DC) and a resistive load of 10 ohms. How much power does it use?
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Not necessarily uses power but no electricity is moving so no heat is created....

Thought experiment: I think one ohm equals to one volt or something so wouldn't be like 2 volts or something.... I don't know.... You only learn so much in a classroom....
 
Don't say I didn't warn you if your brains explode. Or if they slowly ooze out your ears or something :P

Anyway, that would be 14.4W.
 
Not necessarily uses power but no electricity is moving so no heat is created....
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Isn't that what I said?

V = I*R
P = I^2*R
=> P = V^2/R
where V is voltage, R is resistance, and P is power; so as the resistance is increased, for a constant voltage, the power decreases due to decreased current. So Cromewell is correct with 14.4 W which is dissipated through ohmic (aka Joule) heating. So I stand by my initial statement, all the energy would be converted to heat; and I'll stick by that unless someone can give me another energy outlet (note that there is at least one, let's see if anyone can guess it :P).
 
I'll take the wires, AKA the easy one if there is more than 1 :). That is unless they are included in the 10ohm load.
Not true. An infinite resistance, i.e. and open circuit, uses no power and thus generates no heat.
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Using the equations Yeti provided P=I^2 * R ...so it would appear that an infinite resistance would use much more power, but looking at one of the other equations (it is acutally the same, interpolate with ohms law) P = V^2 / R. As R approaches infinity, power approaches 0.

Seriously, brains will explode people. :P
 
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